Mohamed_merah asked . 2021-10-25

How to arrange data

Hello, I use this code which is linked to a Simulink file to simulate and get data used for Artificial Neural Network. The data shown below are saved in structur format and each case contains 30001 data.

So I want to arrange data to get only one matrix with 2 rows and (30001*6) lines by modifying the matlab code or,

save directly the data acquired from MDL file under a matrix of 2 lines and 180006 lines.

Thank you.

 j=1;
for ref_P=10:1:12;  
    for ref_Q=-10:1:-9;   
options = simset('SrcWorkspace','current');
S = sim('gti_V3_15_NN',[],options);   
%%%%%%%%%%%%%%%%%%%%%%%%%%%
Delta       =data_out(:,1); % from workspace
Vom         =data_out(:,2);      
   %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
out(j).Delta=Delta;
out(j).Vom=Vom;
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 Ref_P(j,1) = ref_P;
 Ref_Q(j,1) = ref_Q;
%%%%%%%%%%%%%%%%%%%%%%%%%%%
j= j+1;
   end
end

database , simulink , matrix

Expert Answer

John Michell answered . 2024-12-21 00:33:52

You could likely extract and concatenate this data using a for loop or two, but a more elegent solution may be in using struct2cell(). Your fields will become a column vector of cells with their values being stored in a 3rd dimensional vector. From these, you could extract the data you're looking for using vertcat and brace indexing—See Below:

%% Setup:
bear = struct;
bear(1).paw = (1:100)';
bear(2).paw = (101:200)';
bear(3).paw = (201:300)';
bear(1).tail = (300:-1:201)';
bear(2).tail = (200:-1:101)';
bear(3).tail = (100:-1:1)';

%% Execution: 
tempCell = struct2cell(bear);
vertPaw = vertcat(tempCell{1,1,:}); % Paw is the 1st row, 1st column entry of the cell array
vertTail = vertcat(tempCell{2,1,:}); % Tail is the 2nd row, 1st column entry of the cell array
horzVert = [vertPaw, vertTail]

horzVert = 300×2
     1   300
     2   299
     3   298
     4   297
     5   296
     6   295
     7   294
     8   293
     9   292
    10   291

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