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How to solve this '''Input to EIG must not contain NaN or Inf'''. problem

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How to solve this '''Input to EIG must not contain NaN or Inf'''. problem

Prosenjit Paul asked: Radar , Phased Array System Toolbox , Phased Array Design and Analysis

Struggling with Input to EIG must not contain NaN or Inf in MATLAB? This guide provides solutions to debug and fix NaN/Inf errors in your matrices. Learn how

Expert Answer

Profile picture of Prashant Kumar Prashant Kumar answered . 2025-07-14 13:51:24

num=1;
if num==1
    
   range=[0:3:15]; % range of angular spread in deg

Therefore range will start with 0.

for nn=1:length(range)
    
    if num==1   
       deg=range(nn);  % angular spread in deg  

num is still 1, so the angular speed case applies. range(nn) will be accessed, and as indicated earlier that starts with 0. So deg will be assigned 0.

        sig_ta=deg*ones(1,path)/180*pi;
        sig_te=deg*ones(1,path)/180*pi;

with deg being 0, this makes sig_ta an sig_te all 0.

       b=stat_Rh(sector,ULA,t,r,cl,ray,dt,tH,tW,alpha,mu_ta,mu_te,sig_ta,sig_te,Ta,Te);
and there they are passed to stat_Rh.
Inside stat_Rh
 
temp=temp*exp_lapsec(-(m-i)*dt*sin(mute(ll))+(n-k)*dt*cos(mute(ll))*sin(muta(ll)),sig_te(ll),Te(1)-mute(ll),Te(2)-mute(ll));
    temp=temp*exp_lapsec((n-k)*dt*sin(mute(ll))*cos(muta(ll)),sig_ta(ll),Ta(1)-muta(ll),Ta(2)-muta(ll));
Because sig_te and sig_ta are all 0, then sig_te(ll) and sig_ta(ll) will be 0 in those two calls to exp_lapsec.
 
Inside exp_lapsec,
 
function y= exp_lapsec(c,s,tmin,tmax)

so those 0 will be received into the variable s

b0=s/sqrt(2);

Since s is 0, b0 will be 0.

if tmin>=0
    
    y=1/c0/(2*b0)/(1i*c-1/b0)*(exp((1i*c-1/b0)*tmax)-exp((1i*c-1/b0)*tmin));
    
elseif tmax<=0
    
    y=1/c0/(2*b0)/(1i*c+1/b0)*(exp((1i*c+1/b0)*tmax)-exp((1i*c+1/b0)*tmin));
    
else
    
    y=1/c0/(2*b0)*((1-exp((1i*c+1/b0)*tmin))/(1i*c+1/b0)+(exp((1i*c-1/b0)*tmax)-1)/(1i*c-1/b0));    
    
end
Notice that all three of those cases involve 1/b0. Even without knowing what tmax and tmin are, we can see that these calculations are going to involve working with infinities of different signs. That makes it likely that nan will result, because negative infinity plus positive infinity is nan.
 
All of your sig_ta and sig_te are 0, so all of your results from stat_Rh come out nan, at least for that round. You feed that into eig() and eig() complains about the nan.
 
To repair this, you need to ensure that your sig_ta and sig_te are not 0 for this situation.


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