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working with kolmogrov test

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working with kolmogrov test

hamidreza hamidi asked: kstest kolmogorov ... , AI, Data Science, and Statistics , Statistics and Machine Learning Toolbox

Learn how to effectively use the Kolmogorov-Smirnov test in MATLAB for statistical analysis! Our resource provides practical guidance, examples, and solutions f

Expert Answer

Profile picture of Prashant Kumar Prashant Kumar answered . 2025-07-10 04:58:23

Having only looked at your 2nd block of code, I have some comments and suggestions.
 
1) The parameters for a lognormal distribution are mean and standard deviation in that order. In your code, you're entering them in reverse when you call the cdf() function and this is creating a totally different distribution than you intend to do.
 
 
y = cdf('Lognormal', S_y, S_var, S_mean);    % your code, incorrect
y = cdf('Lognormal', S_y, S_mean, S_var);    % correct

2) This is just a suggestion but it's a bit cleaner to use the makedist() function rather than entering the parameters manually into cdf().

doc cdf

pd = makedist('Lognormal', 'mu', S_mean, 'sigma', S_var); 
y = cdf(pd, S_y);   % instead of cdf('Lognormal', S_y, S_mean, S_var)                  

3) " when I compare my data set with itself, Its result shows me they don't have same distribution." But you aren't comparing your data with itself. You're comparing your data with the results of the cumulative distribution function of your data. The plot below shows the distribution of values from your data (top) and the distribution of values from the CDF. Clearly those distributions differ and the kstest() correctly rejects the null hypothesis.

figure
subplot(2,1,1)
histogram(S_y)
title('mother random variable')
subplot(2,1,2)
histogram(cdf('Lognormal', S_y, S_mean, S_var))
title('CDF distribution')
4) This may be irrelevant given the points above but you are using different means and standard deviations to create the "mother_random_variable" and the cdf() data. For the random variables you are using (0.3, 0.5) for the mean and std but for the cdf you're using the mean and std of the data which are ~(1.5, 0.8)


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