Question
fs = 512; X = [-2 1 -3 5 -1 3 -4 4 -2]; lX = length(X)-1; Y = -diff(X)/2.*cos(pi*(0:1/fs:1-1/fs)') + (X(1:lX)+X(2:lX+1))/2; % Y = [Y(:);X(end)]; plot(0:lX,X,'o',0:1/fs:lX,Y)
Expert Answer
Neeta Dsouza
PhD Expert
Answered Aug 25, 2026
Are you asking this commented line?
% Y=[Y(:);X(end)];
Y(:) represents column vector having all elements (:)
X(end) represents the end element of X
New Y creates the all Y elements and last element of X.
See the following example for better understanding
>> X = [-2 1 -3 5 -1 3 -4 4 -2]
X =
-2.00 1.00 -3.00 5.00 -1.00 3.00 -4.00 4.00 -2.00
>> Y=[1 2 3 4 5 6 7 8 9]
Y =
1.00 2.00 3.00 4.00 5.00 6.00 7.00 8.00 9.00
>> Y=[Y(:);X(end)]
Y =
1.00
2.00
3.00
4.00
5.00
6.00
7.00
8.00
9.00
-2.00
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