Converting a SPICE subcircuit to Simscape component

Prashant Kumar answered . 2024-12-21 22:25:54

component ckt_model_series
% ckt_model_series

    nodes
        node_1 = foundation.electrical.electrical; % node_1
        node_2 = foundation.electrical.electrical; % node_2
        node_3 = foundation.electrical.electrical; % node_3
        node_4 = foundation.electrical.electrical; % node_4
        node_5 = foundation.electrical.electrical; % node_5
        node_6 = foundation.electrical.electrical; % node_6
    end

    variables
        L1 = {value={0,'A'},priority=priority.none};
        L2 = {value={0,'A'},priority=priority.none};
        L3 = {value={0,'A'},priority=priority.none};
    end

    branches
        L1: node_1.i -> node_4.i;
        L2: node_2.i -> node_5.i;
        L3: node_3.i -> node_6.i;
    end

    equations
        value(node_1.v-node_4.v,'V') == 3.93e-09*value(L1.der,'A/s')+0.38*sqrt(3.93e-09*5.35e-09)*value(L2.der,'A/s')+0.45*sqrt( ...
            3.93e-09*5.39e-09)*value(L3.der,'A/s');
        value(node_2.v-node_5.v,'V') == 5.35e-09*value(L2.der,'A/s')+0.38*sqrt(5.35e-09*3.93e-09)*value(L1.der,'A/s')+0.19*sqrt( ...
            5.35e-09*5.39e-09)*value(L3.der,'A/s');
        value(node_3.v-node_6.v,'V') == 5.39e-09*value(L3.der,'A/s')+0.45*sqrt(5.39e-09*3.93e-09)*value(L1.der,'A/s')+0.19*sqrt( ...
            5.39e-09*5.35e-09)*value(L2.der,'A/s');
    end

end

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