Find the optimal value to maximize a function

John Williams answered . 2024-12-03 04:16:08

close all; clear all; clc;

x0_range  = [0.01 0.25 0.5 1];

% System parameters
F = 10000;    % Number of files
S = 100;     % SBS cache capacity (set to 100)
M = 50;      % Cash capacity fraction
alpha = 2; % Path loss exponent for LOS link
c = 3e8;     % Light speed
fr = 1e12;  % Operating frequency
B = 10e6;    % System bandwidth
epsilon = 0.8; % Skewness factor
K = 0.0016;  % Molecular absorption coefficient
P_M = 10^(64/10); % Transmit power MBS
P_S = 10^(30/10); % Transmit power SBS
sigma = 10^(-90/10); % Noise power
N_L = 512;
N_M = 16;
eta = 1;
x2 =30;      % RIS-MBS distance
d_range = 1:1:40;

R = zeros(numel(d_range),numel(x0_range));

for k = 1:numel(x0_range)
    x0 = x0_range(k);
    
    for i = 1:length(d_range)
        d = d_range(i);
        x1 = d-x0; % added line 

%         sum1 = 0;
%         for f = 1:F
%             sum1 = sum1 + f^(-epsilon);
%         end
        f = 1:F;
        sum1 = sum(f.^(-epsilon));
        
%         sum2 = 0;  
%         for f = 1:M
%             sum2 = sum2 + f^(-epsilon)/sum1;
%         end

        f = 1:M;
        sum2 = sum(f.^(-epsilon))/sum1;        

%         sum3 = 0;
%         for f = (M + 1):(M + (S - M) / eta)
%             sum3 = sum3 + (f^(-epsilon)) / sum1;
%         end
%         sum3 = sum3 * eta;
        
        f = (M + 1):(M + (S - M) / eta);
        sum3 = eta*sum(f.^(-epsilon))/sum1;        
        

        beta = (c/(4*pi*fr))^2;  % Spreading loss index
        Rs = B * log2(1 + (P_S * beta * (d-x1)^(-alpha) * exp(-K * (d-x1))) / sigma);
        Rm = B * log2(1 + (P_M * (N_L^2) * N_M * (beta * (d-x0)^(-alpha) * exp(-K * (d-x0))) * (beta * x2^(-alpha) * exp(-K * x2))) / sigma);
        Rt = Rs * (sum2 + sum3) + Rm * (1 - (sum2 + sum3));
        R(i,k) = Rt;
        leg{k} = ['x0 = ' num2str(x0)];

    end

end

    plot(d_range, R, '^-')
    legend(leg)
    xlabel('SBS-RIS Distance, d')
    ylabel('Achievable Rate')  

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