Question
Greetings everyone, I am trying to create a function (without using loops) called LeibnizT that generates a row vector with the first n terms of the Leibniz series, the input argument is just n. My code is attached, thanks! function y=LeibnizT(n) y=(-1).^n/(2.*n+1) end
Expert Answer
Prashant Kumar
PhD Expert
Answered Aug 30, 2026
Think about it. How does that generate a VECTOR? In what you wrote, is n a SCALAR? (Yes)
y=(-1).^n/(2.*n+1)
So how will that create a vector as a result?
What tools can you think of that generate a vector, that do not have a for loop or a while loop? Surely you can think of some tools that will return a vector? In fact, that vector needs to be of length n. Take a shot. Show us what you can think of that gets you closer to what you need. If you do, then I'll see if I can give you another nudge in the correct direction, if necessary.
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